Question

Of the isomeric hexanes, the isomers that give the minimum and maximum number of monochloro derivatives are respectively

• A. $3$-methylpentane and $2,3$-dimethylbutane
• B. $2, 3$-dimethylbutane and $n$-hexane
• C. $2, 2$-dimethylbutane and $2$-methylpentane
• D. $2, 3$-dimethylbutane and $2$-methylpentane
• E. $2$-methylpentane and $2, 2$-dimethylbutane

Answer 1

Answer: (D)

The possible isomers of hexane are

Out of these structure (iii) and (i) have respectively minimum and maximum number of monochloroderivatives
For structure (iii),

[Only 2 monochloroderivatives (minimum) are possible]
For structure (i),

[5 monochloroderivatives (maximum) are possible]