Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
Nylon-6,10 is prepared by the condensation polymerisation of
Q. Nylon-6,10 is prepared by the condensation polymerisation of
1152
219
Polymers
Report Error
A
adipic acid and hexamethylenediamine
B
sebacic acid and hexamethylene-diamine
C
sebacic acid and hexamethylene-amine
D
none of the above
Solution:
Sebacic acid
[
H
OOC
—
(
C
H
2
)
8—
COO
H
]
and hexamethylene diamine
[
H
2
N
—
(
C
H
2
)
6
—
N
H
2
]
,