Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
Nylon-6,10 is prepared by the condensation polymerisation of
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. Nylon-6,10 is prepared by the condensation polymerisation of
Polymers
A
adipic acid and hexamethylenediamine
B
sebacic acid and hexamethylene-diamine
C
sebacic acid and hexamethylene-amine
D
none of the above
Solution:
Sebacic acid $\left[HOOC—\left(CH_2\right)8—COOH\right]$ and hexamethylene diamine $\left[H_{2}N—\left(CH_{2}\right)_{6}—NH_{2}\right]$,