Number of ways in which 6 different mangoes can be distributed between 3 children so that each child gets at least 2 mangoes, is

Question

Number of ways in which 6 different mangoes can be distributed between 3 children so that each child gets at least 2 mangoes, is (A) 15 (B) 45 (C) 60 (D) 90

Tardigrade Admin · Accepted Answer

(6 !/2 ! 2 ! 2 !) ⋅ (1/3 !) ⋅ 3 !=90

Q. Number of ways in which 6 different mangoes can be distributed between 3 children so that each child gets at least 2 mangoes, is

15

45

60

90

$\frac{6 !}{2 ! 2 ! 2 !} \cdot \frac{1}{3 !} \cdot 3! = 90$

Q. Number of ways in which 6 different mangoes can be distributed between 3 children so that each child gets at least 2 mangoes, is

15

45

60

90

2!2!2!6!​⋅3!1​⋅3!=90

$\frac{6 !}{2 ! 2 ! 2 !} \cdot \frac{1}{3 !} \cdot 3! = 90$