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  4. Number of ways in which 6 different mangoes can be distributed between 3 children so that each child gets at least 2 mangoes, is

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Q. Number of ways in which 6 different mangoes can be distributed between 3 children so that each child gets at least 2 mangoes, is

Permutations and Combinations

Solution:

$\frac{6 !}{2 ! 2 ! 2 !} \cdot \frac{1}{3 !} \cdot 3 !=90$