Number of unpaired electrons in O2 molecule is:

Question

Number of unpaired electrons in O2 molecule is: (A) zero (B) one (C) two (D) four

Tardigrade Admin · Accepted Answer

The molecular orbital elctronic configuration of O2 is - O2(16e-)=σ 1s2σ *1s2σ 2s2σ *2s2σ 2px2 π 2py2π 2pz2π *2py1π *2pz1 Hence, it has two unpaired Iectrons and B paramagnetic.

Q. Number of unpaired electrons in $O_{2}$ molecule is:

zero

one

two

four

The molecular orbital elctronic configuration of $O_{2}$ is -
$O_{2} (16 e^{-}) = σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2} σ 2 p x^{2}$ $π 2 p y^{2} π 2 p z^{2} π^{} 2 p y^{1} π^{} 2 p z^{1}$ Hence, it has two unpaired Iectrons and B paramagnetic.

Q. Number of unpaired electrons in O2​ molecule is:

zero

one

two

four

The molecular orbital elctronic configuration of O2​ is - O2​(16e−)=σ1s2σ∗1s2σ2s2σ∗2s2σ2px2 π2py2π2pz2π∗2py1π∗2pz1 Hence, it has two unpaired Iectrons and B paramagnetic.

Q. Number of unpaired electrons in $O_{2}$ molecule is:

The molecular orbital elctronic configuration of $O_{2}$ is -
$O_{2} (16 e^{-}) = σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2} σ 2 p x^{2}$ $π 2 p y^{2} π 2 p z^{2} π^{} 2 p y^{1} π^{} 2 p z^{1}$ Hence, it has two unpaired Iectrons and B paramagnetic.