Q. Number of unpaired electrons in $ {{O}_{2}} $ molecule is:
MGIMS WardhaMGIMS Wardha 2005
Solution:
The molecular orbital elctronic configuration of $ {{O}_{2}} $ is -
$ {{O}_{2}}(16{{e}^{-}})=\sigma 1{{s}^{2}}{{\sigma }^{*}}1{{s}^{2}}\sigma 2{{s}^{2}}{{\sigma }^{*}}2{{s}^{2}}\sigma 2p{{x}^{2}} $ $ \pi 2p{{y}^{2}}\pi 2p{{z}^{2}}{{\pi }^{*}}2p{{y}^{1}}{{\pi }^{*}}2p{{z}^{1}} $ Hence, it has two unpaired Iectrons and B paramagnetic.
