Number of unpaired electrons in O2 molecule is

Question

Number of unpaired electrons in O2 molecule is (A) zero (B) one (C) two (D) four

Tardigrade Admin · Accepted Answer

O2=8+8=16 =σ 1s2, overset* mathopσ 1s2,σ 2s2, overset* mathopσ 2s2,σ 2pz2, π 2py2,π 2px2, overset* mathopπ 2py1 overset* mathopπ 2px1 ∴ Number of unpaired electrons = 2

Q. Number of unpaired electrons in $O_{2}$ molecule is

zero

one

two

four

$O_{2} = 8 + 8 = 16$ $= σ 1 s^{2}, σ * 1 s^{2}, σ 2 s^{2}, σ * 2 s^{2}, σ 2 p_{z}^{2},$ $π 2 p_{y}^{2}, π 2 p_{x}^{2}, π * 2 p_{y}^{1} π * 2 p_{x}^{1}$ $∴$ Number of unpaired electrons = 2

Q. Number of unpaired electrons in O2​ molecule is

zero

one

two

four

O2​=8+8=16 =σ1s2,σ∗1s2,σ2s2,σ∗2s2,σ2pz2​, π2py2​,π2px2​,π∗2py1​π∗2px1​ ∴ Number of unpaired electrons = 2

Q. Number of unpaired electrons in $O_{2}$ molecule is

$O_{2} = 8 + 8 = 16$ $= σ 1 s^{2}, σ * 1 s^{2}, σ 2 s^{2}, σ * 2 s^{2}, σ 2 p_{z}^{2},$ $π 2 p_{y}^{2}, π 2 p_{x}^{2}, π * 2 p_{y}^{1} π * 2 p_{x}^{1}$ $∴$ Number of unpaired electrons = 2