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Chemistry
Number of unpaired electrons in O2 molecule is
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Q. Number of unpaired electrons in $ {{O}_{2}} $ molecule is
CMC Medical
CMC Medical 2012
A
zero
B
one
C
two
D
four
Solution:
$ {{O}_{2}}=8+8=16 $ $ =\sigma \,1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}},\sigma 2p_{z}^{2}, $ $ \pi 2p_{y}^{2},\pi 2p_{x}^{2},\overset{*}{\mathop{\pi }}\,2p_{y}^{1}\overset{*}{\mathop{\pi }}\,2p_{x}^{1} $ $ \therefore $ Number of unpaired electrons = 2