Question

Number of moles of $Mn{O}_4^{-}$ required to oxidise one mole of ferrous oxalate completely in acidic medium will be

• A. 0.6 mol
• B. 0.4 mole
• C. 7.5 moles
• D. 0.2 mole

Answer 1

Answer: (A)

No. of moles of $Mn{O}_4^{-}$required to oxidize one mole of $Fe{C}_2{O}_4$ completely in
acidic medium.
$3Mn{O}_4^{-}+24H^{+}+5Fe{C}_2{O}_4⟶3M{n}^{+2}+12H_{2}O+10C{O}_2+5F{e}^{+3}$
5 moles of $Fe{C}_2{O}_4$ reacts with 3 moles of $Mn{O}_4^{-}$.
5moles of $Fe{C}_2{O}_4⟶$ 3moles of $Mn{O}_4^{-}$
1mole of $Fe{C}_2{O}_4⟶\frac{3}{5}$ moles of $Mn{O}_4^{-}$
$\therefore$ The number of moles of $Mn{O}_4^{-}$required to oxidize one mole of ferrous oxalate completely in the acidic medium will be 0.6 moles.