Number of moles of K2Cr2O7 reduced by one mole of Sn2+ ion is

Question

Number of moles of K2Cr2O7 reduced by one mole of Sn2+ ion is (A) (1/3) (B) 3 (C) (1/6) (D) 6

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/9470ad21cc8378646d72c4c6b2142cd6-.png" /> ∵ 3 moles of Sn2+ ions reduce one mole of K2Cr2O7 ∴ 1 mole of Sn2+ ion reduce (1/3) mole of K2Cr2O7

Q. Number of moles of $K_{2} C r_{2} O_{7}$ reduced by one mole of $S n^{2 +}$ ion is

$\frac{1}{3}$

$3$

$\frac{1}{6}$

$6$

$∵ 3$ moles of $S n^{2 +}$ ions reduce one mole of $K_{2} C r_{2} O_{7}$
$∴ 1$ mole of $S n^{2 +}$ ion reduce $\frac{1}{3}$ mole of $K_{2} C r_{2} O_{7}$

Q. Number of moles of K2​Cr2​O7​ reduced by one mole of Sn2+ ion is

31​

3

61​

6

∵3 moles of Sn2+ ions reduce one mole of K2​Cr2​O7​ ∴1 mole of Sn2+ ion reduce 31​ mole of K2​Cr2​O7​

Q. Number of moles of $K_{2} C r_{2} O_{7}$ reduced by one mole of $S n^{2 +}$ ion is

$\frac{1}{3}$

$3$

$\frac{1}{6}$

$6$

$∵ 3$ moles of $S n^{2 +}$ ions reduce one mole of $K_{2} C r_{2} O_{7}$
$∴ 1$ mole of $S n^{2 +}$ ion reduce $\frac{1}{3}$ mole of $K_{2} C r_{2} O_{7}$