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  4. Number of moles of K2Cr2O7 reduced by one mole of Sn2+ ion is

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Q. Number of moles of $K_2Cr_2O_7$ reduced by one mole of $Sn^{2+}$ ion is

The d-and f-Block Elements

Solution:

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$\because 3 $ moles of $Sn^{2+}$ ions reduce one mole of $K_2Cr_2O_7$
$\therefore 1 $ mole of $Sn^{2+}$ ion reduce $\frac{1}{3}$ mole of $K_2Cr_2O_7$