Q.
Number of integers in the range of function f(x)=log21(x−21)+log2(4x2−4x+1) is (are)
467
106
Relations and Functions - Part 2
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Solution:
f(x)=log2(x−21)−1+log2((2x−1)2) f(x)=−log2(x−21)+log2(2x−1) f(x)=−log2(x−21)+log2(2(x−21)) f(x)=−log2(x−21)+log22+log2(x−21) f(x)=1, so the range of f(x) is {1}