Question

Number of $Fe$ atoms in $100g$ Haemoglobin if it contains $0.33\%$ $Fe$. (Atomic mass of $Fe=56$ )

• A. $0.035\times 10^{23}$
• B. $35$
• C. $3.5\times 10^{23}$
• D. $7\times 10^8$

Answer 1

Answer: (A)

Mass of $Fe=100\times \frac{0.33}{100}=0.33g$
$\therefore$ Moles of $Fe=\frac{0.33}{56}=5.89\times 10^{-3}$ mole
$\therefore$ Number of atom of $Fe=5.89\times 10^{-3}\times 6.022\times 10^{23}$
$=0.035\times 10^{23}$ atom