Question

Number of $Fe$ atoms in $100\, g$ Haemoglobin if it contains $0.33 \%$ $Fe$. (Atomic mass of $Fe =56$ )

• A. $0.035 \times 10^{23}$
• B. $35$
• C. $3.5 \times 10^{23}$
• D. $7 \times 10^{8}$

Answer 1

Answer: (A)

Mass of $Fe =100 \times \frac{0.33}{100}=0.33\, g$
$\therefore $ Moles of $Fe =\frac{0.33}{56}=5.89 \times 10^{-3}$ mole
$\therefore $ Number of atom of $Fe =5.89 \times 10^{-3} \times 6.022 \times 10^{23}$
$=0.035 \times 10^{23}$ atom