Question

Number of atoms in $558.5gmFe$ (atomic weight of $Fe=55.85gmmo{l}^{-1}$ ) is :

• A. twice that in $60gm$ Carbon
• B. $6.023\times 10^{22}$
• C. Half that in $8gmHe$
• D. $558.5\times 6.023\times 10^{23}$

Answer 1

Answer: (A)

No. of atoms of $Fe=\frac{558.5}{558.5}\times 10\times N_A\times 1$
$=10N_A$ atoms
Which twice $60gm$ of carbon atoms