Question

Number of atoms in $558.5gmFe$ (atomic weight of $Fe=55.85gmmol^{- 1}$ ) is :

• A. twice that in $60gm$ Carbon
• B. $6.023\times 10^{22}$
• C. Half that in $8gmHe$
• D. $558.5\times 6.023\times 10^{23}$

Answer 1

Answer: (A)

No. of atoms of $Fe=\frac{558 . 5}{558 . 5}\times 10\times N_{A}\times 1$
$=10N_{A}$ atoms
Which twice $60gm$ of carbon atoms