Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments ' B ' and ' C ' of mass numbers 105 and 115. The binding energy of nucleons in ' B ' and ' C ' is 6.4 MeV per nucleon. The energy Q released per fission will be :

Question

Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments ' B ' and ' C ' of mass numbers 105 and 115. The binding energy of nucleons in ' B ' and ' C ' is 6.4 MeV per nucleon. The energy Q released per fission will be : (A) 0.8 MeV (B) 275 MeV (C) 220 MeV (D) 176 MeV

Tardigrade Admin · Accepted Answer

Q =( B . E ) P -( B . E ) R =(105+115)(6.4)-(220)(5.6) =176 MeV

$0.8 M e V$

$275 M e V$

$220 M e V$

$176 M e V$

$Q = (B . E)_{P} - (B . E)_{R}$
$= (105 + 115) (6.4) - (220) (5.6)$
$= 176 M e V$

Q. Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6MeV. It splits in two fragments ' B ' and ' C ' of mass numbers 105 and 115. The binding energy of nucleons in ' B ' and ' C ' is 6.4MeV per nucleon. The energy Q released per fission will be :

0.8MeV

275MeV

220MeV

176MeV

Q=(B.E)P​−(B.E)R​ =(105+115)(6.4)−(220)(5.6) =176MeV

$0.8 M e V$

$275 M e V$

$220 M e V$

$176 M e V$

$Q = (B . E)_{P} - (B . E)_{R}$
$= (105 + 115) (6.4) - (220) (5.6)$
$= 176 M e V$