1. Tardigrade
  2. Question
  3. Physics
  4. Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments ' B ' and ' C ' of mass numbers 105 and 115. The binding energy of nucleons in ' B ' and ' C ' is 6.4 MeV per nucleon. The energy Q released per fission will be :

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Q. Nucleus A is having mass number $220$ and its binding energy per nucleon is $5.6 \,MeV$. It splits in two fragments ' $B$ ' and ' $C$ ' of mass numbers $105$ and $115$. The binding energy of nucleons in ' $B$ ' and ' $C$ ' is $6.4 MeV$ per nucleon. The energy $Q$ released per fission will be :

JEE MainJEE Main 2022Nuclei

Solution:

$Q =( B . E )_{ P }-( B . E )_{ R }$
$=(105+115)(6.4)-(220)(5.6)$
$=176 \,MeV$