Question

Nucleus $A$ having $Z=17$ and equal number of protons and neutrons has $1.2MeV$ binding energy per nucleon. Another nucleus $B$ of $Z=12$ has total $26$ nucleons and $1.8MeV$ binding energy per nucleons. The difference of binding energy of $B$ and $A$ will be ___$MeV$.

Answer 1

Answer: 6

For A mass number $=34$
Total binding energy $=1.2\times 34=40.8MeV$
For $B$ mass number $=26$
total binding energy $=1.8\times 26MeV$
$=46.8MeV$
Difference of $BE=6MeV$