1. Tardigrade
  2. Question
  3. Physics
  4. Nucleus A having Z=17 and equal number of protons and neutrons has 1.2 MeV binding energy per nucleon. Another nucleus B of Z=12 has total 26 nucleons and 1.8 MeV binding energy per nucleons. The difference of binding energy of B and A will be MeV.

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Q. Nucleus $A$ having $Z=17$ and equal number of protons and neutrons has $1.2 MeV$ binding energy per nucleon. Another nucleus $B$ of $Z=12$ has total $26$ nucleons and $1.8 MeV$ binding energy per nucleons. The difference of binding energy of $B$ and $A$ will be ___$MeV$.

JEE MainJEE Main 2023Nuclei

Solution:

For A mass number $=34$
Total binding energy $=1.2 \times 34=40.8\, MeV$
For $B$ mass number $=26$
total binding energy $=1.8 \times 26 \,MeV$
$=46.8\, MeV$
Difference of $BE =6\, MeV$