NH 3 is oxidized to NO 2 by O 2 (air) in basic medium. Number of equivalent of NH 3 oxidized by 1 mole of O 2 is

Question

NH 3 is oxidized to NO 2 by O 2 (air) in basic medium. Number of equivalent of NH 3 oxidized by 1 mole of O 2 is (A) 4 (B) 5 (C) 6 (D) 7

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/634734c2cf9b1361ef368c0b63204b6f-.png" /> 1 mole O 2 oxidises =(4/5) mol of NH 3 =(4/5) × 5 equivalent of NH 3 =4

Q. $N H_{3}$ is oxidized to $N O_{2}$ by $O_{2}$ (air) in basic medium. Number of equivalent of $N H_{3}$ oxidized by $1$ mole of $O_{2}$ is

4

5

6

7

1 mole $O_{2}$ oxidises $= \frac{4}{5} m o l$ of $N H_{3}$
$= \frac{4}{5} \times 5$ equivalent of $N H_{3}$
$= 4$

Q. NH3​ is oxidized to NO2​ by O2​ (air) in basic medium. Number of equivalent of NH3​ oxidized by 1 mole of O2​ is

4

5

6

7

1 mole O2​ oxidises =54​mol of NH3​ =54​×5 equivalent of NH3​ =4

Q. $N H_{3}$ is oxidized to $N O_{2}$ by $O_{2}$ (air) in basic medium. Number of equivalent of $N H_{3}$ oxidized by $1$ mole of $O_{2}$ is

1 mole $O_{2}$ oxidises $= \frac{4}{5} m o l$ of $N H_{3}$
$= \frac{4}{5} \times 5$ equivalent of $N H_{3}$
$= 4$