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  4. NH 3 is oxidized to NO 2 by O 2 (air) in basic medium. Number of equivalent of NH 3 oxidized by 1 mole of O 2 is

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Q. $NH _3$ is oxidized to $NO _2$ by $O _2$ (air) in basic medium. Number of equivalent of $NH _3$ oxidized by $1$ mole of $O _2$ is

General Principles and Processes of Isolation of Elements

Solution:

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1 mole $O _2$ oxidises $=\frac{4}{5} mol$ of $NH _3$
$=\frac{4}{5} \times 5$ equivalent of $NH _3$
$=4$