Moment of inertia of a rod of mass M and length L about an axis passing through a point midway between centre and end is

Question

Moment of inertia of a rod of mass M and length L about an axis passing through a point midway between centre and end is (A)  (ML2/6)  (B)  (ML2/12)  (C)  (7ML2/24)  (D)  (7ML2/48)

Tardigrade Admin · Accepted Answer

I=IC M+M x2 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/5f272f2d20c9416aa3bbb0dfacbdd0ae-.png" /> =(M L2/12)+M[(L/4)]2 =(M L2/12)+(M L2/16) =(7 M L2/48)

Q. Moment of inertia of a rod of mass $M$ and length $L$ about an axis passing through a point midway between centre and end is

$\frac{M L ^{2}}{6}$

$\frac{M L ^{2}}{12}$

$\frac{7 M L ^{2}}{24}$

$\frac{7 M L ^{2}}{48}$

$I = I_{CM} + M x^{2}$

$= \frac{M L ^{2}}{12} + M [\frac{L}{4}]^{2}$
$= \frac{M L ^{2}}{12} + \frac{M L ^{2}}{16}$
$= \frac{7 M L ^{2}}{48}$

Q. Moment of inertia of a rod of mass M and length L about an axis passing through a point midway between centre and end is

6ML2​

12ML2​

247ML2​

487ML2​