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Q. Moment of inertia of a rod of mass $ M $ and length $ L $ about an axis passing through a point midway between centre and end is

MHT CETMHT CET 2009

Solution:

$I=I_{C M}+M x^{2}$
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$=\frac{M L^{2}}{12}+M\left[\frac{L}{4}\right]^{2}$
$=\frac{M L^{2}}{12}+\frac{M L^{2}}{16}$
$=\frac{7 M L^{2}}{48}$