Molecular orbital electronic configuration for ' X' anion is: K K*(σ 2 s)2(σ* 2 s)2(π 2 px)2(π 2 py)2(σ 2 pz)2 (π* 2 px)1. The anion ' X' is :

Question

Molecular orbital electronic configuration for ' X' anion is: K K*(σ 2 s)2(σ* 2 s)2(π 2 px)2(π 2 py)2(σ 2 pz)2 (π* 2 px)1. The anion ' X' is : (A)  N2-  (B)  O2-  (C)  N22-  (D)  O22-

Tardigrade Admin · Accepted Answer

Given, electronic configuration of anion X is: σ 1 s2, σ* 1 s2, σ 2 s2, σ* 2 s2, σ 2 px2, π 2 py2, σ 2 pz2 π* 2 px1 ∴ total number of electrons of anion X=15 Hence, the anion X is N 2-

Q. Molecular orbital electronic configuration for $^{'} X^{'}$ anion is : $K K^{} (σ 2 s)^{2} (σ^{} 2 s)^{2} (π 2 p_{x})^{2} (π 2 p_{y})^{2} (σ 2 p_{z})^{2}$ $(π^{*} 2 p_{x})^{1}$ . The anion ' $X$ ' is :

$N_{2}^{-}$

$O_{2}^{-}$

$N_{2}^{2 -}$

$O_{2}^{2 -}$

Given, electronic configuration of anion $X$ is :
$σ 1 s^{2}, σ^{} 1 s^{2}, σ 2 s^{2}, σ^{} 2 s^{2}, σ 2 p_{x}^{2}, π 2 p_{y}^{2}, σ 2 p_{z}^{2} π^{*} 2 p_{x}^{1}$
$∴$ total number of electrons of anion $X = 15$
Hence, the anion $X$ is $N_{2}^{-}$

Q. Molecular orbital electronic configuration for ′X′ anion is : KK∗(σ2s)2(σ∗2s)2(π2px​)2(π2py​)2(σ2pz​)2 (π∗2px​)1. The anion ' X' is :

N2−​

O2−​

N22−​

O22−​