Molarity of H2SO4 is 18 M. Its density is 1.8 g/mL. Hence, molality is

Question

Molarity of H2SO4 is 18 M. Its density is 1.8 g/mL. Hence, molality is (A) 36 (B) 200 (C) 500 (D) 18

Tardigrade Admin · Accepted Answer

Given, molarity of H2SO4=18M That means 18 moles of H2SO4 are present in 1000 mL of solution. ∴ Mass of solution =1800-1764=36g Molalitry=(moles of solute × 1000/mass of solvent) =(18× 1000/36) 500m

Q. Molarity of $H_{2} S O_{4}$ is 18 M. Its density is 1.8 g/mL. Hence, molality is

36

200

500

18

Given, molarity of $H_{2} S O_{4} = 18 M$ That means 18 moles of $H_{2} S O_{4}$ are present in 1000 mL of solution. $∴$ Mass of solution $= 1800 - 1764 = 36 g$ $M o l a l i t ry = \frac{m o l es o f so l u t e \times 1000}{ma ss o f so l v e n t}$ $= \frac{18 \times 1000}{36}$ $500 m$

Q. Molarity of H2​SO4​ is 18 M. Its density is 1.8 g/mL. Hence, molality is

36

200

500

18

Given, molarity of H2​SO4​=18M That means 18 moles of H2​SO4​ are present in 1000 mL of solution. ∴ Mass of solution =1800−1764=36g Molalitry=massofsolventmolesofsolute×1000​ =3618×1000​ 500m

Q. Molarity of $H_{2} S O_{4}$ is 18 M. Its density is 1.8 g/mL. Hence, molality is

Given, molarity of $H_{2} S O_{4} = 18 M$ That means 18 moles of $H_{2} S O_{4}$ are present in 1000 mL of solution. $∴$ Mass of solution $= 1800 - 1764 = 36 g$ $M o l a l i t ry = \frac{m o l es o f so l u t e \times 1000}{ma ss o f so l v e n t}$ $= \frac{18 \times 1000}{36}$ $500 m$