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Q.
Molarity of $ {{H}_{2}}S{{O}_{4}} $ is 18 M. Its density is 1.8 g/mL. Hence, molality is
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Solution:
Given, molarity of $ {{H}_{2}}S{{O}_{4}}=18M $ That means 18 moles of $ {{H}_{2}}S{{O}_{4}} $ are present in 1000 mL of solution. $ \therefore $ Mass of solution $ =1800-1764=36g $ $ Molalitry=\frac{moles\,of\,solute\,\times 1000}{mass\,of\,solvent} $ $ =\frac{18\times 1000}{36} $ $ 500m $