Molar conductivity of a solution is 1.26 × 102 ohm -1 cm 2 mol -1 . Its molarity is 0.01 . Its specific conductivity will be

Question

Molar conductivity of a solution is 1.26 × 102 ohm -1 cm 2 mol -1 . Its molarity is 0.01 . Its specific conductivity will be (A) 1.26 × 10-25 ohm -1 cm -1 (B) 1.26 × 10-3 ohm -1 cm -1 (C) 1.26 × 10-4 ohm -1 cm -1 (D) 0.0063 ohm -1 cm -1

Tardigrade Admin · Accepted Answer

Applying, Lambdam=( kappa × 1000/ text Molarity ) kappa=(1.26 × 102 × 0.01/1000)=1.26 × 10-3 ohm -1 cm -1

Q. Molar conductivity of a solution is $1.26 \times 1 0^{2} o h m^{- 1}$ $c m^{2} m o l^{- 1} .$ Its molarity is $0.01$ . Its specific conductivity will be

$1.26 \times 1 0^{- 25} o h m^{- 1} c m^{- 1}$

$1.26 \times 1 0^{- 3} o h m^{- 1} c m^{- 1}$

$1.26 \times 1 0^{- 4} o h m^{- 1} c m^{- 1}$

$0.0063 o h m^{- 1} c m^{- 1}$

Applying, $Λ_{m} = \frac{κ \times 1000}{Molarity}$

$κ = \frac{1.26 \times 1 0 ^{2} \times 0.01}{1000} = 1.26 \times 1 0^{- 3} o h m^{- 1} c m^{- 1}$

Q. Molar conductivity of a solution is 1.26×102ohm−1 cm2mol−1. Its molarity is 0.01 . Its specific conductivity will be

1.26×10−25ohm−1cm−1

1.26×10−3ohm−1cm−1

1.26×10−4ohm−1cm−1

0.0063ohm−1cm−1