Question

Molar conductivity of a solution is $1.26 \times 10^{2} \,ohm ^{-1}$ $cm ^{2} mol ^{-1} .$ Its molarity is $0.01 $ . Its specific conductivity will be

• A. $1.26 \times 10^{-25} \,ohm ^{-1} cm ^{-1}$
• B. $1.26 \times 10^{-3}\, ohm ^{-1} cm ^{-1}$
• C. $1.26 \times 10^{-4} \,ohm ^{-1} cm ^{-1}$
• D. $0.0063 \,ohm ^{-1} cm ^{-1}$

Answer 1

Answer: (B)

Applying, $\Lambda_{m}=\frac{\kappa \times 1000}{\text { Molarity }}$

$\kappa=\frac{1.26 \times 10^{2} \times 0.01}{1000}=1.26 \times 10^{-3} ohm ^{-1} cm ^{-1}$