Molar conductance of saturated BaSO 4 soulution is 400. ohm -1 cm 2 mol -1 and its specific conductance is 4 × 10-5 ohm -1. Hence solubility product value of BaSO 4 can be concluded as x × 10-8 M 2. Identify x

Question

Molar conductance of saturated BaSO 4 soulution is 400. ohm -1 cm 2 mol -1 and its specific conductance is 4 × 10-5 ohm -1. Hence solubility product value of BaSO 4 can be concluded as x × 10-8 M 2. Identify x (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Molar conductance =( specific conductance × 1000) /( solubility ) Solubility =(4 × 10-5 × 1000/400)=10-4 Ksp =(10-4)2=10-8

Q. Molar conductance of saturated $B a S O_{4}$ soulution is $400. o h m^{- 1} c m^{2} m o l^{- 1}$ and its specific conductance is $4 \times 1 0^{- 5} o h m^{- 1}$ . Hence solubility product value of $B a S O_{4}$ can be concluded as $x \times 1 0^{- 8} M^{2}$ . Identify $x$

Molar conductance
$= ($ specific conductance $\times 1000) / ($ solubility $)$
Solubility $= \frac{4 \times 1 0 ^{- 5} \times 1000}{400} = 1 0^{- 4}$
$Ks p = (1 0^{- 4})^{2} = 1 0^{- 8}$

Q. Molar conductance of saturated BaSO4​ soulution is 400.ohm−1cm2mol−1 and its specific conductance is 4×10−5ohm−1. Hence solubility product value of BaSO4​ can be concluded as x×10−8M2. Identify x

Molar conductance =( specific conductance ×1000)/( solubility ) Solubility =4004×10−5×1000​=10−4 Ksp=(10−4)2=10−8

Q. Molar conductance of saturated $B a S O_{4}$ soulution is $400. o h m^{- 1} c m^{2} m o l^{- 1}$ and its specific conductance is $4 \times 1 0^{- 5} o h m^{- 1}$ . Hence solubility product value of $B a S O_{4}$ can be concluded as $x \times 1 0^{- 8} M^{2}$ . Identify $x$

Molar conductance
$= ($ specific conductance $\times 1000) / ($ solubility $)$
Solubility $= \frac{4 \times 1 0 ^{- 5} \times 1000}{400} = 1 0^{- 4}$
$Ks p = (1 0^{- 4})^{2} = 1 0^{- 8}$