1. Tardigrade
  2. Question
  3. Chemistry
  4. Molar conductance of saturated BaSO 4 soulution is 400. ohm -1 cm 2 mol -1 and its specific conductance is 4 × 10-5 ohm -1. Hence solubility product value of BaSO 4 can be concluded as x × 10-8 M 2. Identify x

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Q. Molar conductance of saturated $BaSO _{4}$ soulution is $400. ohm ^{-1} cm ^{2} mol ^{-1}$ and its specific conductance is $4 \times 10^{-5} ohm ^{-1}$. Hence solubility product value of $BaSO _{4}$ can be concluded as $x \times 10^{-8} M ^{2}$. Identify $x$

Electrochemistry

Solution:

Molar conductance
$=($ specific conductance $\times 1000) /($ solubility $)$
Solubility $=\frac{4 \times 10^{-5} \times 1000}{400}=10^{-4}$
$Ksp =\left(10^{-4}\right)^{2}=10^{-8}$