Metal M crystallizes into a FCC lattice with the edge length of 4.0 × 10-8 cm. The atomic mass of the metal is g / mol. (Nearest integer). (Use: N A =6.02 × 1023 mol -1, density of metal, .M =9.03 g cm -3)

Question

Metal M crystallizes into a FCC lattice with the edge length of 4.0 × 10-8 cm. The atomic mass of the metal is g / mol. (Nearest integer). (Use: N A =6.02 × 1023 mol -1, density of metal, .M =9.03 g cm -3) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

a =4 × 10-8 cm d =9.03 g / ml d =( ZM / N A a 3) M =(9.03 × 6.02 × 1023 × 64 × 10-24/4)=86.97

Q. Metal $M$ crystallizes into a FCC lattice with the edge length of $4.0 \times 1 0^{- 8} c m$ . The atomic mass of the metal is ___ $g / m o l$ . (Nearest integer).
(Use : $N_{A} = 6.02 \times 1 0^{23} m o l^{- 1}$ , density of metal, $M = 9.03 g c m^{- 3})$

$a = 4 \times 1 0^{- 8} c m$
$d = 9.03 g / m l$
$d = \frac{ZM}{N _{A} a ^{3}}$
$M = \frac{9.03 \times 6.02 \times 1 0 ^{23} \times 64 \times 1 0 ^{- 24}}{4} = 86.97$

Q. Metal M crystallizes into a FCC lattice with the edge length of 4.0×10−8cm. The atomic mass of the metal is ___ g/mol. (Nearest integer). (Use : NA​=6.02×1023mol−1, density of metal, M=9.03gcm−3)

a=4×10−8cm d=9.03g/ml d=NA​a3ZM​ M=49.03×6.02×1023×64×10−24​=86.97

Q. Metal $M$ crystallizes into a FCC lattice with the edge length of $4.0 \times 1 0^{- 8} c m$ . The atomic mass of the metal is ___ $g / m o l$ . (Nearest integer).
(Use : $N_{A} = 6.02 \times 1 0^{23} m o l^{- 1}$ , density of metal, $M = 9.03 g c m^{- 3})$

$a = 4 \times 1 0^{- 8} c m$
$d = 9.03 g / m l$
$d = \frac{ZM}{N _{A} a ^{3}}$
$M = \frac{9.03 \times 6.02 \times 1 0 ^{23} \times 64 \times 1 0 ^{- 24}}{4} = 86.97$