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Q. Metal $M$ crystallizes into a FCC lattice with the edge length of $4.0 \times 10^{-8}\, cm$. The atomic mass of the metal is ___ $g / mol$. (Nearest integer).
(Use : $N _{ A }=6.02 \times 10^{23} \,mol ^{-1}$, density of metal, $\left.M =9.03 \,g\, cm ^{-3}\right)$

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Solution:

$ a =4 \times 10^{-8} cm $
$ d =9.03 \,g / ml $
$ d =\frac{ ZM }{ N _{ A } a ^3}$
$ M =\frac{9.03 \times 6.02 \times 10^{23} \times 64 \times 10^{-24}}{4}=86.97$