Question

Maximum oxidation state of $Cr$ is:

• A. 3
• B. 4
• C. 6
• D. 7

Answer 1

Answer: (C)

$Cr$ (atomic number $=24$)
$=1s^2,2s^{2}2p^6,3s^{2}3p^{6}3d^5,4s^1$
shows, oxidation state from $+1$ to $+6$.