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Q. Maximum oxidation state of $ Cr $ is:

Rajasthan PMTRajasthan PMT 2002Redox Reactions

Solution:

$Cr$ (atomic number $=24$)
$=1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{5}, 4 s^{1}$
shows, oxidation state from $+1$ to $+6$.