Question

Match the compounds in Column I with their characteristic test(s)/ reaction(s) given in Column II:

Column I		Column II
A	$H_{2}N-\stackrel{+}{N}{H}_{3}C{l}^{-}$	P	Sodium fusion extract of the compound gives Prussian blue colour with $FeS{O}_4$.
B		Q	Gives positive $FeC{l}_3$ test.
C		R	Gives white precipitate with $AgN{O}_3$.
D		S	Reacts with aldehydes to form the corresponding hydrazone derivative

• A. $(A)\to (R);(S),(B)\to (P),(Q);(C)\to (Q),(R);(D)\to (P)$ (S)
• B. $(A)\to (P);(S),(B)\to (P),(Q);(C)\to (P),(Q),(R)$ $(D)\to (P),(S)$
• C. $(A)\to (R);(S),(B)\to (P),(Q);(C)\to (P),(Q),(R);$ $(D)\to (P),(S)$
• D. $(A)\to (R);(S),(B)\to (P),(Q);(C)\to (P),(Q),(R);$ $(D)\to (P),(Q)$

Answer 1

Answer: (C)

The observed changes can be explained on the basis that sodium fusion extract give Prussian blue colour on treatment with $FeS{O}_4$ when nitrogen is present along with carbon.
Phenolic and carboxylate groups give positive test with $FeC{l}_3$ White precipitate with $AgN{O}_3$ is formed when chloride ions are present.
Formation of hydrazine derivatives takes place on reaction of hydrazine with aldehyde.