Question

Match the compounds in Column I with their characteristic test(s)/ reaction(s) given in Column II:

Column I		Column II
A	$H_2N - \overset{+}{N}H_3Cl^-$	P	Sodium fusion extract of the compound gives Prussian blue colour with $FeSO _{4}$.
B		Q	Gives positive $FeCl _{3}$ test.
C		R	Gives white precipitate with $AgNO _{3}$.
D		S	Reacts with aldehydes to form the corresponding hydrazone derivative

• A. $( A ) \rightarrow( R ) ;( S ),( B ) \rightarrow( P ),( Q ) ;( C ) \rightarrow( Q ),( R ) ;( D ) \rightarrow( P )$ (S)
• B. $( A ) \rightarrow( P ) ;( S ),( B ) \rightarrow( P ),( Q ) ;( C ) \rightarrow( P ),( Q ),( R )$ $( D ) \rightarrow( P ),( S )$
• C. $( A ) \rightarrow( R ) ;( S ),( B ) \rightarrow( P ),( Q ) ;( C ) \rightarrow( P ),( Q ),( R ) ;$ $( D ) \rightarrow( P ),( S )$
• D. $( A ) \rightarrow( R ) ;( S ),( B ) \rightarrow( P ),( Q ) ;( C ) \rightarrow( P ),( Q ),( R ) ;$ $( D ) \rightarrow( P ),( Q )$

Answer 1

Answer: (C)

The observed changes can be explained on the basis that sodium fusion extract give Prussian blue colour on treatment with $FeSO _{4}$ when nitrogen is present along with carbon.
Phenolic and carboxylate groups give positive test with $Fe Cl _{3}$ White precipitate with $AgNO _{3}$ is formed when chloride ions are present.
Formation of hydrazine derivatives takes place on reaction of hydrazine with aldehyde.