Question

Match the column $I$ with column $II$ and mark the appropriate choice

Column $I$		Column $I$
(A)	Mass of $H_2$ produced when $0.5$ mole of zinc reacts with excess of $HCl$	(i)	$3.01\times 10^{23}$ molecules
(B)	Mass of all atoms of a compound with formula $C_{70}{H}_{22}$	(ii)	$6.023\times 10^{23}$ molecules
(C)	Number of molecules in $35.5g$ of $C{l}_2$	(iii)	$1.43\times 10^{-21}$
(D)	Number of molecules in $64g$ of $S{O}_2$	(iv)	$1g$

• A. $\left(A\right)\to \left(ii\right),\left(B\right)\to \left(i\right),\left(C\right)\to \left(iv\right),\left(D\right)\to \left(iii\right)$
• B. $\left(A\right)\to \left(i\right),\left(B\right)\to \left(ii\right),\left(C\right)\to \left(iii\right),\left(D\right)\to \left(iv\right)$
• C. $\left(A\right)\to \left(iv\right),\left(B\right)\to \left(iii\right),\left(C\right)\to \left(i\right),\left(D\right)\to \left(ii\right)$
• D. $\left(A\right)\to \left(iv\right),\left(B\right)\to \left(iii\right),\left(C\right)\to \left(ii\right),\left(D\right)\to \left(i\right)$

Answer 1

Answer: (C)

$(A):Zn+2HCl\to ZnC{l}_2+H_2$
$1$ mole of $Zn$ produces $2g$ of $H_2$
$0.5$ mole of $Zn$ will produce $1g$ of $H_2$
$(B):C_{70}{H}_{22}$
Molar mass $=862$
Mass of atoms $=862/6.023\times 10^{23}$
$=1.43\times 10^{-21}g$
$(C):71gofC{l}_2=6.023\times 10^{23}$ Molecules
$35.5g$ of $C{l}_2=3.01\times 10^{23}$ Molecules
$(D):$ Molar mass of $S{O}_2=64=1$ mole
$64g$ of $S{O}_2=6.023\times 10^{23}$ Molecules