Question

Match the column $I$ with column $II$ and mark the appropriate choice

Column $I$		Column $I$
(A)	Mass of $H_{2}$ produced when $0.5$ mole of zinc reacts with excess of $HCl$	(i)	$3.01\times 10^{23}$ molecules
(B)	Mass of all atoms of a compound with formula $C_{70} H_{22}$	(ii)	$6.023\times 10^{23}$ molecules
(C)	Number of molecules in $35.5 \,g$ of $Cl_2$	(iii)	$1.43\times 10^{-21}$
(D)	Number of molecules in $64\, g$ of $SO_{2}$	(iv)	$1\,g$

• A. $\left(A\right) \rightarrow\left(ii\right), \left(B\right) \rightarrow \left(i\right), \left(C\right) \rightarrow \left(iv\right), \left(D\right) \rightarrow \left(iii\right) $
• B. $\left(A\right) \rightarrow\left(i\right), \left(B\right) \rightarrow \left(ii\right), \left(C\right) \rightarrow \left(iii\right), \left(D\right) \rightarrow \left(iv\right) $
• C. $\left(A\right) \rightarrow\left(iv\right), \left(B\right) \rightarrow \left(iii\right), \left(C\right) \rightarrow \left(i\right), \left(D\right) \rightarrow \left(ii\right) $
• D. $\left(A\right) \rightarrow\left(iv\right), \left(B\right) \rightarrow \left(iii\right), \left(C\right) \rightarrow \left(ii\right), \left(D\right) \rightarrow \left(i\right) $

Answer 1

Answer: (C)

$(A) : Zn + 2HCl \to ZnCl_2 +H_2$
$1$ mole of $Zn$ produces $2 \,g$ of $H_2$
$0.5$ mole of $Zn$ will produce $1\, g$ of $H_2$
$(B) : C_{70} H_{22}$
Molar mass $ = 862$
Mass of atoms $=862/6.023 \times 10^{23}$
$=1.43\times 10^{-21} \, g$
$(C) : 71\, g of Cl_2 = 6.023 \times 10^{23}$ Molecules
$35.5 \,g$ of $ Cl_2= 3.01 \times 10^{23}$ Molecules
$(D) :$ Molar mass of $SO_2 = 64 = 1$ mole
$64\,g $ of $SO_2 = 6.023 \times 10^{23}$ Molecules