Manganese (VI) has ability to disproportionate in acidic solution. The difference in oxidation states of two ions it forms in acidic solution is

Question

Manganese (VI) has ability to disproportionate in acidic solution. The difference in oxidation states of two ions it forms in acidic solution is  (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

MnO 42- disproportionates in a neutral or acidic solution to give MnO 4-and Mn +4 3 MnO 42-+3 H + longrightarrow 2 MnO 4-+ MnO 2+2 H 2 O O.S. of Mn in MnO 4-=+7 O.S. of Mn in MnO 2=+4 difference =3

Q. Manganese (VI) has ability to disproportionate in acidic solution. The difference in oxidation states of two ions it forms in acidic solution is _____

$M n O_{4}^{2 -}$ disproportionates in a neutral or acidic solution to give
$M n O_{4}^{-}$ and $M n^{+ 4}$
$3 M n O_{4}^{2 -} + 3 H^{+} ⟶ 2 M n O_{4}^{-} + M n O_{2} + 2 H_{2} O$
O.S. of $M n$ in $M n O_{4}^{-} = + 7$
O.S. of $M n$ in $M n O_{2} = + 4$
difference $= 3$

Q. Manganese (VI) has ability to disproportionate in acidic solution. The difference in oxidation states of two ions it forms in acidic solution is _____

MnO42−​ disproportionates in a neutral or acidic solution to give MnO4−​and Mn+4 3MnO42−​+3H+⟶2MnO4−​+MnO2​+2H2​O O.S. of Mn in MnO4−​=+7 O.S. of Mn in MnO2​=+4 difference =3

$M n O_{4}^{2 -}$ disproportionates in a neutral or acidic solution to give
$M n O_{4}^{-}$ and $M n^{+ 4}$
$3 M n O_{4}^{2 -} + 3 H^{+} ⟶ 2 M n O_{4}^{-} + M n O_{2} + 2 H_{2} O$
O.S. of $M n$ in $M n O_{4}^{-} = + 7$
O.S. of $M n$ in $M n O_{2} = + 4$
difference $= 3$