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Q.
Manganese (VI) has ability to disproportionate in acidic solution. The difference in oxidation states of two ions it forms in acidic solution is _____
$MnO _{4}^{2-}$ disproportionates in a neutral or acidic solution to give
$MnO _{4}^{-}$and $Mn ^{+4}$
$3 MnO _{4}^{2-}+3 H ^{+} \longrightarrow 2 MnO _{4}^{-}+ MnO _{2}+2 H _{2} O$
O.S. of $Mn$ in $MnO _{4}^{-}=+7$
O.S. of $Mn$ in $MnO _{2}=+4$
difference $=3$