Magnetic moments of V (Z = 23), Cr (Z = 24) and Mn (Z = 25) are x, y, z. Hence

Question

Magnetic moments of V (Z = 23), Cr (Z = 24) and Mn (Z = 25) are x, y, z. Hence (A) z< y< x (B) x= y= z (C) x< z< y (D) x< y< Z

Tardigrade Admin · Accepted Answer

Magnetic moments = √n(n+2)B.M. where n is the. number of unpaired electron V (Z = 23) (At) 3d3 4s2 n=3,√15 BM = x Cr (Z= 24) (Ar) 3d5 4s n = 6, √48 BM =y Mn (Z = 25) (Ar) 3d5 4s2 n = 5, √35 BM =z

Q. Magnetic moments of $V (Z = 23), C r (Z = 24)$ and Mn $(Z = 25)$ are $x, y, z .$ Hence

$z < y < x$

$x = y = z$

$x < z < y$

$x < y < Z$

Magnetic moments = $n (n + 2)$ B.M. where n is the. number of unpaired electron
$V (Z = 23) (A t) 3 d^{3} 4 s^{2} n = 3, 15 BM = x$
$C r (Z = 24) (A r) 3 d^{5} 4 s n = 6, 48 BM = y$
$M n (Z = 25) (A r) 3 d^{5} 4 s^{2} n = 5, 35 BM = z$

Q. Magnetic moments of V(Z=23),Cr(Z=24) and Mn (Z=25) are x,y,z. Hence

z<y<x

x=y=z

x<z<y

x<y<Z