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  4. Magnetic moments of V (Z = 23), Cr (Z = 24) and Mn (Z = 25) are x, y, z. Hence

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Q. Magnetic moments of $V (Z = 23), Cr (Z = 24) $ and Mn $(Z = 25)$ are $x, y, z.$ Hence

Structure of Atom

Solution:

Magnetic moments = $\sqrt{n\left(n+2\right)}$B.M. where n is the. number of unpaired electron
$V (Z = 23) (At) 3d^{3} 4s^{2} n=3,\sqrt{15} BM = x $
$Cr (Z= 24) (Ar) 3d^{5} 4s n = 6, \sqrt{48} BM =y$
$Mn (Z = 25) (Ar) 3d^{5} 4s^{2} n = 5, \sqrt{35} BM =z$