M and M √3 are the magnetic dipole moments of the two magnets which are joined to form a cross figure. The inclination of the system with the field, if their combination is suspended freely in a uniform external magnetic field B is

Question

M and M √3 are the magnetic dipole moments of the two magnets which are joined to form a cross figure. The inclination of the system with the field, if their combination is suspended freely in a uniform external magnetic field B is (A) θ=30° (B) θ=45° (C) θ=60° (D) θ=15°

Tardigrade Admin · Accepted Answer

In equilibrium, τ1=τ2 M B sin θ=√3 M B sin (90°-θ) ∴ tan θ=√3 ⇒ θ=60°

Q. $M$ and $M 3$ are the magnetic dipole moments of the two magnets which are joined to form a cross figure. The inclination of the system with the field, if their combination is suspended freely in a uniform external magnetic field $B$ is

$θ = 3 0^{\circ}$

$θ = 4 5^{\circ}$

$θ = 6 0^{\circ}$

$θ = 1 5^{\circ}$

In equilibrium, $τ_{1} = τ_{2}$
$MB sin θ = 3 MB sin (9 0^{\circ} - θ)$
$∴ tan θ = 3$
$\Rightarrow θ = 6 0^{\circ}$

Q. M and M3​ are the magnetic dipole moments of the two magnets which are joined to form a cross figure. The inclination of the system with the field, if their combination is suspended freely in a uniform external magnetic field B is

θ=30∘

θ=45∘

θ=60∘

θ=15∘