Lowering of vapour pressure is highest for

Question

Lowering of vapour pressure is highest for (A) 0.2 m urea (B) 0.1 m glucose (C) 0.1 m MgSO 4 (D) 0.1 m BaCl 2

Tardigrade Admin · Accepted Answer

Lowering in vapour pressure is directly proportional to molality which in turn is directly proportional to

n

factor (no. of ions it gives)
The concentration of urea, i.e,

0.2 M

is much more than glucose,

M g S O_{4} & B a C l_{2}

Therefore urea will have greater molality \& therefore it will have highest vapour pressure.

Q. Lowering of vapour pressure is highest for