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Q. Lowering of vapour pressure is highest for

BHUBHU 1997Solutions

Solution:

Lowering in vapour pressure is directly proportional to molality which in turn is directly proportional to $n$ factor (no. of ions it gives)
The concentration of urea, i.e, $0.2 M$ is much more than glucose, $MgSO _{4} \& BaCl _{2}$

Therefore urea will have greater molality \& therefore it will have highest vapour pressure.