Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
displaystyle lim n arrow ∞ n sin (2 π/3 n) ⋅ cos (2 π/3 n) is
Q.
n
→
∞
lim
n
sin
3
n
2
π
⋅
cos
3
n
2
π
is
3692
219
KCET
KCET 2010
Limits and Derivatives
Report Error
A
1
15%
B
3
π
16%
C
6
π
14%
D
3
2
π
55%
Solution:
n
→
∞
lim
n
⋅
sin
3
n
2
π
⋅
cos
3
n
2
π
=
n
→
∞
lim
n
{
(
3
n
2
π
)
(
sin
3
n
2
π
)
}
⋅
cos
3
n
2
π
×
3
n
2
π
=
(
1
)
⋅
cos
(
0
∘
)
×
3
2
π
{
∵
θ
→
∞
lim
1/
θ
sin
1/
θ
=
1
}
=
1
⋅
3
2
π
=
3
2
π