Light of wavelength 4000 A0 is incident on a metal surface of work function 2.5 e V. Given h=6.62 × 10-34 Js, c = 3 × 108 m/s, the maximum KE of photoelectrons emitted and the corresponding stopping potential are respectively

Question

Light of wavelength 4000 A0 is incident on a metal surface of work function 2.5 e V. Given h=6.62 × 10-34 Js, c = 3 × 108 m/s, the maximum KE of photoelectrons emitted and the corresponding stopping potential are respectively (A) 0. 6 eV, 0.6 V (B) 2.5 eV, 2.5 V (C) 3.1 eV,3.1 V (D) 0.6 eV, 0.3 V

Tardigrade Admin · Accepted Answer

According to given question, Maximum kinetic energy is

K

.

E

.,

< b r / > < b r / > \frac{h C}{λ} - W = K . E . < b r / >\Rightarrow K . E . = 4.14 \times 1 0^{- 15} \times 3 \times 1 0^{8} - 2.5 < b r / >\Rightarrow K . E . = 0.605 e V < b r / >\Rightarrow K . E . \approx 0.6 e V < b r / > < b r / >

So,
From definition of stopping potential,
K.E.

= e \times V_{0}

[Where

V_{0}

is stopping potential]

0.6 e V = e V_{0}

\Rightarrow V_{0} = 0.6 v o lt s

Q. Light of wavelength 4000A0 is incident on a metal surface of work function 2.5eV. Given h=6.62×10−34Js,c=3×108m/s, the maximum KE of photoelectrons emitted and the corresponding stopping potential are respectively

0. 6 eV, 0.6 V

2.5 eV, 2.5 V

3.1 eV,3.1 V

0.6 eV, 0.3 V

Q. Light of wavelength $4000 A^{0}$ is incident on a metal surface of work function $2.5 e V$ . Given $h = 6.62 \times 1 0^{- 34} J s, c = 3 \times 1 0^{8} m / s,$ the maximum KE of photoelectrons emitted and the corresponding stopping potential are respectively