Let the positive numbers a, b, c, d be in A.P. Then (1/abc), (1/abd), (1/acd), (1/bcd) are in

Question

Let the positive numbers a, b, c, d be in A.P. Then (1/abc), (1/abd), (1/acd), (1/bcd) are in (A) A. P. (B) G. P. (C) A. G. P. (D) none of these

Tardigrade Admin · Accepted Answer

a, b, c, d are in A. P. Reversing the terms, d, c, b, a are also in A. P. Dividing each term by a b c d, (1/abc), (1/abd), (1/acd), (1/bcd) are in A. P.

Q. Let the positive numbers $a, b, c, d$ be in $A . P$ . Then
$\frac{1}{ab c}, \frac{1}{ab d}, \frac{1}{a c d}, \frac{1}{b c d}$ are in

$A . P .$

$G . P .$

$A . G . P .$

none of these

$a, b, c, d$ are in $A . P$ .
Reversing the terms, $d, c, b, a$ are also in $A . P$ .
Dividing each term by $ab c d$ ,
$\frac{1}{ab c}, \frac{1}{ab d}, \frac{1}{a c d}, \frac{1}{b c d}$ are in $A . P .$

Q. Let the positive numbers a,b,c,d be in A.P. Then abc1​,abd1​,acd1​,bcd1​ are in

A.P.

G.P.

A.G.P.